一瓶汽水2元，2空瓶可换1汽水，4瓶盖可换1汽水，问10元能喝多少瓶汽水

1 def duihuan(pingzi,gaizi,qian,jiu): 2     pingzi = pingzi+(qian/2) 3     gaizi = gaizi+(qian/2) 4     jiu = jiu+qian/2 5     qian = qian%2 6  7     gaizi = gaizi+pingzi/2 8     jiu = jiu+pingzi/2 9     pingzi = pingzi%2+pingzi/210 11     pingzi = pingzi+gaizi/412     jiu = jiu+gaizi/413     gaizi = gaizi%4+gaizi/414     print pingzi,"--",gaizi,"--",jiu,"--",qian15     result = [pingzi,gaizi,qian,jiu]16     return result17 18 aaa = duihuan(0,0,10,0)19 while(aaa[0]>=2 or aaa[1]>=4 or aaa[2]>=2):20     aaa = duihuan(aaa[0],aaa[1],aaa[2],aaa[3])

 

结果：

4 -- 4 -- 8 -- 0

3 -- 3 -- 11 -- 0

3 -- 1 -- 13 -- 0

2 -- 2 -- 14 -- 0

1 -- 3 -- 15 -- 0

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